What Are the Final Velocities After a Two-Dimensional Collision?

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SUMMARY

The discussion focuses on calculating the final velocities of two objects after a two-dimensional collision. The first object has a mass of 6 kg and an initial velocity of 3 m/s, while the second object, also 6 kg, starts at rest. After the collision, the first object moves at a 40-degree angle to the left of its original path, while the second object moves to the right of the first's original path. The relevant equations for momentum conservation in both x and y directions are provided, confirming that the masses can be omitted due to their equality.

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hdo
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problem:
before - 1st object: m=6kg, v=3m/s
2nd object: m=6kg, v=0m/s
after - 1st object move off in a direction 40 degree to the left of its original path
2nd move to the right of the first's original path
find the speech of each object after the collision
equations:
x-direction: m1v1ix + m2v2ix = m1v1fx + m2v2fx
y-direction: m1v1iy + m2v2iy = m1v1fy + m2v2fy
 
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Welcome to PF!

Hi hdo! Welcome to PF!: :smile:

(try using the X2 tag just above the Reply box :wink:)
hdo said:
… 2nd move to the right of the first's original path

Do you mean at 90º?

ok, those are the correct equations … now put the numbers in …

what do you get? :smile:

(btw, all the masses are the same, 6 kg, so you can leave them all out! :wink:)
 

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