What are the Magnitude and Angle of Vectors in Terms of their Components?

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SUMMARY

The discussion focuses on calculating the magnitude and angle of vectors based on their components. For the velocity vector with an x component of -75 m/s and a y component of 35 m/s, the magnitude is determined using the formula A = √(Ax² + Ay²), while the angle is calculated using angle = tan⁻¹(Ay/Ax) with an adjustment of 180 degrees due to the negative x component. In the case of the force vector with a magnitude of 50 lb in the third quadrant, the angle must also be adjusted, but the magnitude is already provided. Participants emphasize the importance of visualizing vectors on an x-y coordinate plane to accurately determine angles.

PREREQUISITES
  • Understanding of vector components (x and y)
  • Familiarity with trigonometric functions (tan, arctan)
  • Knowledge of the Pythagorean theorem for calculating magnitudes
  • Ability to interpret angles in a coordinate system
NEXT STEPS
  • Learn how to use the atan2 function for angle calculations
  • Study vector representation in a Cartesian coordinate system
  • Explore the concept of vector addition and subtraction
  • Practice drawing vectors and calculating their magnitudes and angles
USEFUL FOR

Students in physics or engineering, educators teaching vector analysis, and anyone involved in mechanics or kinematics who needs to understand vector components and their graphical representations.

Susanem7389
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Rewrite the following vectors in terms of their magnitude and angle (counterclockwise from the +x direction)
a) A velocity vector with an x component of -75 m/s and a y component of 35 m/s
- I found the magnitude by using A= square root of ( Ax squared plus Ay squared ), however I did not get the correct answer for the angle. I used the formula angle = tan -1 ( Ay/ Ax)

b) A force vector with a magnitude of 50 lb that is in the third quadrant with an x component whose magnitude is 40 lb.
- I could not find the correct magnitude and angle with the same formula used in part A.
 
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Could you show your angel for part a) as well as magnitude and angel for part b)?
 
Note that your calculator cannot distinguish arctan(1/1) from arctan(-1/-1).
Rule of thumb... if the x-component is negative, add 180 degrees to what your calculator tells you when using arctan. (Some calculators may have something like an atan2 function.)
 
For part A, adding 180 degrees to what the calculator gave me, I got the correct answer, however it did not work for part b.
 
Susanem7389 said:
For part A, adding 180 degrees to what the calculator gave me, I got the correct answer, however it did not work for part b.

You'll have to show your work...
 
I would strongly suggest drawing out each of these vectors on an x-y coordinate plane so you can see exactly what the angles the formulas are giving you. The vector angle is always going to be measured with respect to the +x direction, in a counter-clockwise fashion; in other words, a vector in this +x direction would have an angle of 0 degrees.

Try to not just remember formulas, look at the right triangles the vector magnitude, x-component, and y-component are forming. The magnitude is going to be the hypotenuse of the right triangle that is formed.

for b) They give the the magnitude of the vector already, you just need to find the angle. Remember that the angle will be measure from the +x direction rotating counter-clockwise until it meets the vector in question.
 

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