What Are the Oxidation Numbers in Zn(NO3)2?

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SUMMARY

The oxidation numbers in zinc nitrate, Zn(NO3)2, are determined as follows: Zinc (Zn) has an oxidation number of +2, while the nitrate ion (NO3) has a -1 charge overall. In the nitrate ion, nitrogen (N) has an oxidation number of +5, and each oxygen (O) has an oxidation number of -2. This results in a balanced equation where Zn contributes +2 to neutralize the charge from two nitrate ions, confirming the common oxidation state of Zn in this compound.

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[SOLVED] Oxidation #s For Zn(NO3)2 ?

Homework Statement



I need to ballance the redox reaction underneath using the 1/2 reaction method but the problem is that I can't figure out the oxidation #s for Zn(NO3)2 and after that, I'm having problems balancing it.

Homework Equations



Zn + HNO3 ---> Zn(NO3)2 + 2NH4NO3 + H2O

The Attempt at a Solution



On the reactants side, the oxidation # for Zn is 0, For H->+1 for N--->+5 for O3--->-2/atom
 
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NO3 should carry it's original Oxidation numbers when becoming Zn(NO3)2 since it's splits from H which carries a +1 charge. That would make NO3- (a -1 oxidation number for the entire ion since you already stated that N=+5 and O=-2 per molecule). Combining 2 NO3- groups with Zn would give Zn an oxidation number of 2+ in order to cancel out the 2- charge from the 2 NO3 groups, which is a common oxidation number for Zn.
 

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