MHB What Are the Possible Jordan Forms and Characteristic Polynomial of T?

  • Thread starter Thread starter darksidemath
  • Start date Start date
  • Tags Tags
    Forms
Click For Summary
The discussion focuses on finding the possible Jordan forms and characteristic polynomial of the linear transformation T defined on Q^3, given the equation (T^7 + 2I)(T^2 + 3T + 2I)^2 = 0. The characteristic polynomial is derived from the factors, revealing eigenvalues -1 and -2 from the quadratic factor, and a real eigenvalue -√[7]{2} along with six complex roots from the cubic factor. The Jordan form will consist of diagonal blocks for distinct eigenvalues and Jordan blocks for repeated eigenvalues. Specifically, the Jordan form includes a block for the eigenvalues -1 and -2, and a diagonal entry for -√[7]{2}, along with submatrices for complex conjugate pairs. Understanding these components is crucial for determining the overall structure of T's Jordan form.
darksidemath
Messages
2
Reaction score
0
Hi guys i have this problem in my linear algebra curse . let $T:\mathbb{Q}^3→\mathbb{Q}^3$ a linear application s.t $(T^7+2I)(T^2+3T+2I)^2=0$
can you find all possible Jordan forms of T and related characteristic polynomial ? I am totally lost and that is the first time i see this type of problem
 
Physics news on Phys.org
First, do you understand what the "Jordan form" of a matrix is? It is another matrix having the real eigenvalues of the original matrix on its main diagonal possibly with "1" just above each diagonal. If all eigenvalues are distinct, the matrix is diagonalizable and its "Jordan form" IS that diagonal matrix. When there is a duplicate eigenvalue, there will be a block with that eigenvalue on the diagonal as many times as the multiplicity of the eigenvalue and "1" just above each eigenvalue.

Note that x^3+ 3x+ 2= (x+ 1)(x+ 2). So -1 and -2 are eigenvalues and the "Jordan form" will include the block [math]\begin{bmatrix}-1 & 0 \\ 0 & -2\end{bmatrix}[/math].

The other factor, [math]x^7+ 2[/math] has the single real zero, [math]-\sqrt[7]{2}[/math] and 6 complex roots, three pairs of complex conjugates. The Jordan form matrix will have [math]-\sqrt[7]{2}[/math] on the main diagonal. a pair of complex conjugates, say a+ bi and a- bi, will give a submatrix of the form [math]\begin{bmatrix}a & b \\ -b & a \end{bmatrix}[/math]
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K