What Are the Singular Points of the Differential Equation w'' + z*w' + kw = 0?

Click For Summary
SUMMARY

The discussion focuses on identifying and classifying singular points of the differential equation w'' + z*w' + kw = 0, where k is an unknown constant. The primary singular point identified is at z = ∞, which is classified as irregular after a transformation x = 1/z reveals that the limit as x approaches 0 diverges. The participants also discuss finding the first term of the asymptotic solution as z approaches infinity, suggesting the use of a power series expansion w = ∑ a_n z^n.

PREREQUISITES
  • Understanding of second-order linear homogeneous differential equations.
  • Familiarity with singular points and their classification (ordinary, regular, irregular).
  • Knowledge of power series solutions and asymptotic analysis.
  • Experience with transformations in differential equations, specifically x = 1/z.
NEXT STEPS
  • Study the classification of singular points in differential equations.
  • Learn about asymptotic solutions and their derivation techniques.
  • Explore power series methods for solving differential equations.
  • Investigate the implications of irregular singular points on solution behavior.
USEFUL FOR

Mathematicians, physics students, and engineers dealing with differential equations, particularly those interested in singular point analysis and asymptotic solutions.

Ice Vox
Messages
3
Reaction score
0
Hi,
I'm asked to find and classify the singular points of a function w(z) in the differential equation:

w''+z*w'+kw=0 where k is some unknown constant.

The only singular point I notice is $$z=\infty$$. Is that right?

I did a transformation x=1/z and examined the singular point at x=0 and found that the limit as $$x\to0$$ gives $$2-1/x^2$$ which blows up, meaning the singular point is irregular. Does that mean that the singular point z=infinity is irregular also?

It also asks me to find the first term of the asymptotic solution as $$z\to\infty$$ for each of the two solutions. Does this mean just put it in a power series solution $$w=\sum_{n=0}^\infty a_nz^n$$ and see what happens?

Thanks!
 
Physics news on Phys.org
CWolf said:
Hi,
I'm asked to find and classify the singular points of a function w(z) in the differential equation:

w''+z*w'+kw=0 where k is some unknown constant.

The only singular point I notice is $$z=\infty$$. Is that right?

I did a transformation x=1/z and examined the singular point at x=0 and found that the limit as $$x\to0$$ gives $$2-1/x^2$$ which blows up, meaning the singular point is irregular. Does that mean that the singular point z=infinity is irregular also?

It also asks me to find the first term of the asymptotic solution as $$z\to\infty$$ for each of the two solutions. Does this mean just put it in a power series solution $$w=\sum_{n=0}^\infty a_nz^n$$ and see what happens?

Thanks!

Wellcome on MHB CWolf!...

In general a second order linear homogeneous DE can be written as...

$\displaystyle y^{\ ''} + f_{1} (x)\ y^{\ '} + f_{2} (x)\ y =0\ (1)$

We have the following possible cases...

a) if $f_{1} (x)$ and $f_{2} (x)$ are both analytic in x=a, then x=a is an ordinary point...

b) if $f_{1} (x)$ has a pole up to order 1 and $f_{2}(x)$ a pole up to order 2 in x=a, then x=a is a regular singular point...

c) in any other case x=a is a singular point...

In Your case is $f_{1}(x) = x$ and $f_{2} = k$, both analytic in $\mathbb R$, so that there are no singular points...

Kind regards

$\chi$ $\sigma$
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K