What Are the Solutions to bx^2 + cx + a = 0 for Any Constants a, b, and c?

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SUMMARY

The solutions to the quadratic equation bx² + cx + a = 0 can be determined using the quadratic formula, x = (-c ± √(c² - 4ab)) / (2b). For specific constants a = 3.1, b = -2.2, and c = -4.3, substituting these values into the formula yields the solutions x ≈ 1.22 and x ≈ -1.12, calculated to three significant digits. This discussion emphasizes the application of the quadratic formula for solving any quadratic equation defined by constants a, b, and c.

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1. Suppose y = bx^2 +cx + a
a.) in terms of a, b, and c, what values of x make y=0?

b.) if a=3.1, b= -2.2 and c=-4.3 evaluate those solutions to 3 significant digits:


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3. I am not really sure how to solve for what the question is asking for in part a, and for part b do I just plug those values into a quadratic formula for an answer? Any help is appreciated
 
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for part 'b', you would want to use the quadratic formula.
 


Part a is really very similar to part b, it is just a much more general case, which applies to any constants a, b and c. It is basically saying that for any given constants, what are the solutions to the equation:

bx^2 +cx + a = 0
 

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