What are the steps for graphically solving a system of equations?

Click For Summary

Homework Help Overview

The discussion revolves around solving a system of equations graphically, specifically focusing on two sets of equations involving linear and quadratic functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss estimating intersection points from graphical representations and question how to verify these points algebraically. There is also a focus on substituting values back into the equations to check for correctness.

Discussion Status

Some participants have provided guidance on verifying graphical solutions by substitution into the original equations. There is an ongoing exploration of algebraic methods to find solutions, with one participant seeking further assistance to continue their work.

Contextual Notes

Participants are navigating the challenge of checking their graphical solutions without fully understanding algebraic methods yet. There is an emphasis on ensuring accuracy in calculations and interpretations of the equations.

duki
Messages
264
Reaction score
0

Homework Statement



Solve the system of equations graphically.

Homework Equations



1)
4x - y = 5
y = 4 - 5x^2


2)
2x^2 + y^2 = 33
x^2 - y^2 = 12

The Attempt at a Solution



The answers I got for the intersecting points are:
1)
(1, -1)

And

2)
(+/- 3.7, +/- 1.8)

These are estimates from graphing, but I'm not sure if I'm close... I don't know how to check myself algebraically yet... =/
 
Physics news on Phys.org
You should be able to at least substitute your graphically-obtained points into the equations.
 
I did that mostly...

but for the equations like y = 4 - 5x^2, is that the same as saying:

y = 4 - 5(-1)^2?
or would it bet
y = 4 - 5(-1^2)?

for that particular equations here are my points:

x...| y
0 ....4
+/-.89 ...0
+/- 1 ...-1
+/- 2 ...-3
 
for your first problem you have found a possible solution at (1,-1).

Your equations are:
y= 4x -5
and
y= 4 - 5 x 2

Plugging x = 1 into each of these yields:

y = 4(1) -5 = -1

Thus your point is a solution for this equation.

Repeat for the second equation.

y = 4 - 5(-1) 2 = 4 -5 = -1

Thus your solution works in both equations and is an intersection point.

Do the same thing with your second problem.
 
groovy, good to know I'm on the right path...

could you show me how to solve algebraically (#1)? If you could give me a start I'll work on it and let you know where I get...
 
In my last post I expressed both equatons of your first problem as y expressed in terms of x. Eliminate y by setting them equal, then solve for x.

y= 4x -5
y = 4 - 5x 2
4x -5 = 4 - 5x 2
5x 2 + 4x - 9 = 0

Can you finish?
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
3
Views
2K
Replies
4
Views
2K
Replies
4
Views
2K
Replies
6
Views
4K
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
2K