What are the velocities of the particles after a perfectly inelastic collision?

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SUMMARY

The discussion focuses on calculating the final velocities of two particles after a perfectly inelastic collision. Particle 1, with mass m and initial velocity v, collides with particle 2, which has mass 3m and is initially stationary. The correct final velocity of both particles after the collision is determined to be (1/4)v, correcting the initial miscalculation of 4v. The conservation of momentum equation m_1v_1 + m_2v_2 = (m_1 + m_2)v_f is essential for solving this problem.

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Homework Statement



Particle 1 has initial velocity v, directed to the right, and particle 2 is initially stationary.
Let the mass of particle 1 be m and the mass of particle 2 be 3m. If the collision is perfectly inelastic, what are the velocities of the two particles after the collision?

Homework Equations



[tex]m_{}1[/tex][tex]v_{}1[/tex] + [tex]m_{}2[/tex][tex]v_{}2[/tex]= ([tex]m_{}1[/tex]+[tex]m_{}2[/tex])v

The Attempt at a Solution



[tex]m_{}1[/tex][tex]v_{}1[/tex] = (m + 3m)v
[tex]v_{}1[/tex] = ((4m)v)/m

so I get [tex]v_{}1[/tex] and ][tex]v_{}2[/tex] (since they are stuck together) to be 4v, but it says I'm off by a multiplative factor. Any ideas?
 
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You solved for the wrong velocity. Solve for [itex]v_f[/itex], not [itex]v_1[/itex]. [itex]v_1[/itex] is given as "v".
 
yep, it's (1/4)*v, thanks.
 

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