What Can the Wave Function for Hydrogen Tell Us About Its Properties?

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SUMMARY

The discussion centers on the wave function of a hydrogen atom in the 2s state, specifically represented by the equation ψ2s(r) = (1/4√(2πao3/2))(2 - r/ao)e(-r/2ao). When evaluating this wave function at r = ao (0.0529 nm), the resulting value is approximately 1.57 x 1014 m-3. The discussion emphasizes that while wave functions are essential for calculating observable quantities in quantum mechanics, they do not inherently possess physical meaning themselves.

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Homework Statement



Suppose a hydrogen atom is in the 2s stat, with its wav function given by:

\psi_2_s (r) = \frac{1}{4\sqrt(2\pi a_o^\frac{3}{2})} (2-\frac{r}{a_o}) e^(-\frac{r}{2a_o})

Taking r = a_o, calculate \psi_2_s (a_o)

Homework Equations




The Attempt at a Solution



Since r=a_o=0.0529 nm, I get \frac{1.57*10^(14)}{ m^3}

Now, my question is "what is the meaning of this value?
 
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Well, the units of a 3-D wave function should have m3/2 in the denominator (i.e. the units are m-3/2).

I'm not sure people actually ascribe physical meaning to the value of a wavefunction. I think of wavefunctions as a calculational tool in determining observable quantities such as position, momentum, energy, etc. QM is all about measurable quantities or observables.

Hope that helps.
 

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