What Charge Value Would Keep the Moon in Orbit by Electrical Force?

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SUMMARY

The discussion centers on calculating the charge value necessary to maintain the Moon's orbit around the Earth using electrical attraction instead of gravitational force. The relevant formulae include Newton's law of gravitation, Gm1m2/r^2, and Coulomb's law, kQ^2/r^2. To find the correct charge (Q), one must also incorporate the Moon's orbital velocity, leading to the equation m2v^2/r = kQ^2/r^2. This approach clarifies the relationship between mass, charge, and orbital mechanics.

PREREQUISITES
  • Understanding of Newton's law of gravitation (Gm1m2/r^2)
  • Familiarity with Coulomb's law (kQ^2/r^2)
  • Basic knowledge of orbital mechanics and centripetal force
  • Ability to calculate orbital velocity of celestial bodies
NEXT STEPS
  • Calculate the orbital velocity of the Moon using its mass and radius of orbit
  • Explore the implications of using electrical forces in celestial mechanics
  • Investigate the constants G (gravitational constant) and k (Coulomb's constant) for precise calculations
  • Review the concept of point particles in physics for simplification in calculations
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Students and educators in physics, astrophysics enthusiasts, and anyone interested in the theoretical implications of electrical forces in orbital dynamics.

acissej2487
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Here is my problem:

Suppose that electrical attraction, rather than gravity, were responsible for holding the Moon in orbit around the Earth.
If equal and opposite charges were placed on the Earth and the Moon, what should be the value of Q to maintain the present orbit? Use these data: mass of Earth=5.98*10^24 kg, mass of Moon = 7.35*10^22 kg, radius of orbit=3.84*10^8 m. Treat the Earth and Moon as point particles.


I know that I use Gm1m2/r^2 = kQ2/r^2. But I cannot get the right answer!

Help please :)
 
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I know that I use Gm1m2/r^2 = kQ2/r^2. But I cannot get the right answer!
You have to use m2v^2/r = kQ2/r^2 where m2 is the mass of the moon and v is the velocity of the moon around the earth.
 

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