What Conditions Make a Matrix the Hessian of a Function?

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    Hessian Matrix
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SUMMARY

The discussion centers on the conditions under which a smooth nxn matrix-valued function G(x) can be the Hessian of a function g. It is established that if G_{ij,k} = G_{ik,j} for all indices i, j, and k, then a smooth function g exists such that Hess(g) = G, specifically g_{,ij} = G_{ij}. The participant expresses confidence in constructing a solution for the case n=2 but seeks guidance on generalizing this to higher dimensions and addressing the overdetermined system of partial differential equations (PDEs).

PREREQUISITES
  • Understanding of smooth functions and their properties
  • Familiarity with Hessian matrices in multivariable calculus
  • Knowledge of partial differential equations (PDEs)
  • Experience with matrix calculus and differentiation
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  • Research the theory behind Hessian matrices in higher dimensions
  • Explore methods for solving overdetermined systems of PDEs
  • Study examples of constructing smooth functions from given Hessians
  • Learn about the implications of symmetry in matrix-valued functions
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Mathematicians, particularly those specializing in differential equations, multivariable calculus, and theoretical physics, will benefit from this discussion.

quasar987
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Apparently it is a well-known fact that if [itex]G(x)=(G_{ij}(x_1,\ldots,x_n))[/itex] is a smooth nxn matrix-valued function such that [itex]G_{ij,k}=G_{ik,j}[/itex] for all i,j,k, then there exists a smooth function g such that Hess(g)=G; i.e. [itex]g_{,ij}=G_{ij}[/itex]. ([itex]f_{,k}[/itex] denotes partial differentiation with respect to the kth variable.)

I believe I can construct the solution explicitly in the n=2 case, but I'm not sure how to generalize my argument. Is there an argument to be made about the existence of a solution to this overdetermined system of PDE? Thx!
 

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