What Determines Electric Field Strengths of Two Charged Rods

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Homework Help Overview

The problem involves two charged rods, one glass and one plastic, each 10cm long and placed 4cm apart, with the goal of determining the electric field strengths at specific distances from the glass rod. The context is within electrostatics, particularly focusing on electric fields generated by charged objects.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster expresses confusion about the nature of the problem, initially considering it to be related to capacitors due to the arrangement of the charged rods. They question how to determine when a scenario describes a capacitor versus another configuration. Some participants clarify that the materials involved do not qualify as conductors and suggest focusing on the electric field due to finite lines of charge.

Discussion Status

Participants are exploring the nature of the problem and clarifying the distinction between capacitors and the current setup. Guidance has been provided regarding the need to calculate the electric field from finite line charges and the importance of superimposing the fields from both rods.

Contextual Notes

There is an ongoing discussion about the definitions and characteristics of conductors versus insulators in the context of electric fields, as well as the implications of these definitions for solving the problem. The original poster is seeking clarification on the appropriate formulas to use for calculating electric fields in this scenario.

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Homework Statement


The problem I encountered goes like this: A 10cm long thin glass rod uniformly charged to 10nC and a 10cm long thin plastic rod uniformly charged to -10nC are placed side by side 4cm apart. What are the electric field strengths E1 to E3 at distances 1cm, 2cm, and 3cm from the glass rod along the line connecting the midpoints of the two rods?

Homework Equations


E= η/ε0 = (4πK⋅Q) / A

The Attempt at a Solution


I am not quite confused about getting the answer to this problem but as to how I should approach the problem. I thought that the question was describing a capacitor, since the two rods are charged equally but oppositely. But when I tried to use the formula (as shown above), I realized I have no way to find the area. So, I realized that it was not a capacitor. How would I know, aside from looking at the formula, that the question is not describing a capacitor? Or when it describes a capacitor?
 
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To have a capacitor, you need two conductors near one another carrying equal and opposite charges. That's not what you have here because neither glass nor plastic can be considered as conductors. You need to find the electric field due to finite line of charge and superimpose the two fields.
 
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kuruman said:
To have a capacitor, you need two conductors near one another carrying equal and opposite charges. That's not what you have here because neither glass nor plastic can be considered as conductors. You need to find the electric field due to finite line of charge and superimpose the two fields.
Thank you for your explanation. Which formula should I use if I am solving for the electric field due to finite line of charge?
 

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