- #1

skyturnred

- 118

- 0

## Homework Statement

Here is the question:

I don't quite know what I did wrong. My method is below.

## Homework Equations

## The Attempt at a Solution

f(x)=√x

f'(x)=[itex]\frac{1}{2(x)^{1/2}}[/itex]

f''(x)=[itex]\frac{-1}{(2)(2)(x^{3/2}}[/itex]

a=4

f(a)=2

f'(a)=1/4

f''(a)=[itex]\frac{-1}{4(4^{3})^{1/2}}[/itex]

so wouldn't the second taylor polynomial be what I put in the answer field above? Thanks.