What did I do wrong in calculating the x-component of net displacement?

  • Thread starter Thread starter Joe91090
  • Start date Start date
Click For Summary

Homework Help Overview

The problem involves calculating the x-component of net displacement for a car that travels a specified distance in two segments, with a directional change. The subject area pertains to vector components and trigonometry.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of the law of cosines versus drawing a right triangle to visualize the problem. There are questions about the angles involved and whether the triangle formed is acute or right.

Discussion Status

The discussion is ongoing, with participants providing guidance on visualizing the problem through diagrams. There is an exploration of different interpretations regarding the angles and the components of displacement, but no consensus has been reached on the correct approach.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the methods they can use to solve the problem. There is uncertainty regarding the angles and the configuration of the triangle formed by the car's path.

Joe91090
Messages
54
Reaction score
0
What did I do Wrong ??

Homework Statement



A car travels 2.14km in the x direction then turns left 71.6 degrees to the original direction and travels an additional distance of 2.58km. calculate the x component of the cars net displacement.

Homework Equations



law of cosines

The Attempt at a Solution



plugged knowns into law of cosines equations got 2.78. what did I do wrong ??
 
Physics news on Phys.org


Draw a picture, you should have a right triangle. There is no need for the law of cosines.
 


Ive drawn several pictures does it just look like a right triangle ?
 


Draw a line downwards from the final position to the x-axis...now do you see the right triangle?
 


is your first movemment to the east ?
 


Yes. Isn't yours?
 


yes then your 71.6 degrees left so does yours look acute or obtuse ?
 


well if your saying its a right angle it must be acute. I am still not sure its a right angle
 
  • #10


so the answer would be the displacement from (0,0) to the tip of the other vector ?
 
  • #11
Last edited by a moderator:

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 56 ·
2
Replies
56
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
2K
Replies
3
Views
2K