What Does a Convolution of a Convolution Look Like?

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SUMMARY

The discussion focuses on the mathematical concept of convolution, specifically exploring the convolution of a convolution, denoted as \( h*(f*g) \). The participants clarify the definition of convolution using integral notation, where \( (f*g)(t) \) is defined as \( \int_{-\infty}^\infty f(x)g(t - x) dx \). The final expression for \( (h*(f*g))(t) \) is derived as \( \int_{-\infty}^\infty h(y) \left( \int_{-\infty}^\infty f(x)g(t - y - x) dx \right) dy \), illustrating the layered nature of convolution operations.

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thrillhouse86
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Hi,
can someone please give me an example of what a convolution of a convolution would look like ?

Thanks
 
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What do you mean by "look like"?
 
as in:
<br /> f*g = \int^{\infty}_{-\infty} f(\tau)g(t-\tau) d\tau<br />

what would
h*(f*g) look like ?

-Thrillhouse
 
I should think something along these lines:

(f*g)(t) \stackrel{\mathrm{def}}{=} \displaystyle\int_{-\infty}^\infty f(x)g(t - x) dx

(h*(f*g))(t) = \displaystyle\int_{-\infty}^\infty h(y)(f*g)(t - y) dy = \displaystyle\int_{-\infty}^\infty h(y) \left( \displaystyle\int_{-\infty}^\infty f(x)g(t - y - x) dx \right) dy
 
thanks pbandjay
 

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