What does normalizing a straight line mean?

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SUMMARY

The discussion centers on the normalization of a variable "D" by the value "D1" in the context of calculating the slope of a graph. Participants express confusion regarding the rationale behind this normalization process, suggesting it serves to scale the observed drag against a reference value. The normalization is essential for comparing changes in drag effectively, although the original author's intent remains unclear without additional context from the text.

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Good day,
From the first attachment...

Why is "D" divided by "D1"? The book is saying that it is for normalizing "D" by the value of "D1".
It's not quite clear !

Screenshot_20180312-185202.jpg


The whole formula is to find the slope of this graph.

Screenshot_20180312-185151.jpg
 

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Who knows what the author was thinking. Maybe it is in the context of the remainder of what he has written
 
It is simply some scaling applied, e.g. to compare the observed drag (and its change) to some previously considered value D1.
 
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