MHB What does this Limit mean geometrically?

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The discussion centers on evaluating the limit $\lim_{(x,y) \to (0,0)} \frac{\cos x-1-\frac{x^2}{2}}{x^4+y^4}$ and understanding its geometric implications when approaching along the line $y=0$. It also explores the limit of the function $g(x,y)=\frac{xy}{x^2+y^2}$, concluding that its dependence on the parameter $m$ indicates that the limit does not exist. The conversation further examines whether a limit can be considered existent if it is independent of $m$, suggesting that consistency across paths is crucial for limit existence. Additionally, the discussion touches on checking limits by evaluating them along different axes, highlighting that differing results indicate non-existence. Understanding these concepts is essential for grasping multivariable limits in calculus.
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Hello! (Wave)

I want to find the following limit, if it exists.

$\lim_{(x,y) \to (0,0)} \frac{\cos x-1-\frac{x^2}{2}}{x^4+y^4}$ If we say : let $(x,y) \to (0,0)$ along the line $y=0$ , what exactly does it mean geometrically?

Also, if we want to check whether the limit $\lim_{(x,y) \to (0,0)} g(x,y) $ exists where $g(x,y)=\frac{xy}{x^2+y^2}$, we pick $y=mx$ and since $g(x,mx)$ depends on $m$ we deduce that the limit does not exist.

If $g(x,mx)$ would be independent on $m$, would that mean that the limit exists? If so, why?
 
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evinda said:
Hello! (Wave)

I want to find the following limit, if it exists.

$\lim_{(x,y) \to (0,0)} \frac{\cos x-1-\frac{x^2}{2}}{x^4+y^4}$ If we say : let $(x,y) \to (0,0)$ along the line $y=0$ , what exactly does it mean geometrically?

Also, if we want to check whether the limit $\lim_{(x,y) \to (0,0)} g(x,y) $ exists where $g(x,y)=\frac{xy}{x^2+y^2}$, we pick $y=mx$ and since $g(x,mx)$ depends on $m$ we deduce that the limit does not exist.

If $g(x,mx)$ would be independent on $m$, would that mean that the limit exists? If so, why?

What do you mean by "independent on m"?
 
Prove It said:
What do you mean by "independent on m"?

I mean that the result of the limit isn't a function of $m$...
 
Also, if we want to check if the limit $\lim_{(x,y) \to (0,0)} \frac{\sin{(2x)}-2x+y}{x^3+y}$ exists, we can consider the limit along the line $y=0$ and the limit along $x=0$ and we will see that they are not equal. Is this the only way to see that the limit does not exist?
 
There are probably loads of proofs of this online, but I do not want to cheat. Here is my attempt: Convexity says that $$f(\lambda a + (1-\lambda)b) \leq \lambda f(a) + (1-\lambda) f(b)$$ $$f(b + \lambda(a-b)) \leq f(b) + \lambda (f(a) - f(b))$$ We know from the intermediate value theorem that there exists a ##c \in (b,a)## such that $$\frac{f(a) - f(b)}{a-b} = f'(c).$$ Hence $$f(b + \lambda(a-b)) \leq f(b) + \lambda (a - b) f'(c))$$ $$\frac{f(b + \lambda(a-b)) - f(b)}{\lambda(a-b)}...

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