What does this thing on batteries mean?

[Sam19KY]

Say that 6V battery is connected to a lamp that takes 3V from each coulomb. Does that mean that the battery can supply 6V or dependent upon the need of components in the circuit ?

 

[Svein]

Say that 6V battery is connected to a lamp that takes 3V from each coulomb.

What do you mean? "Take 3V from each coulomb" is totally meaningless.

 

[Sam19KY]

I mean 3 joules of energy from each coulomb.

 

[cnh1995]

Does that mean that the battery can supply 6V or dependent upon the need of components in the circuit ?

It will supply 6V to any lamp connected across it since it is a 6V battery. Work done per unit charge is the potential difference, which is 6V here.

 

[Svein]

I will try to answer what I think you mean (not what you asked). The capacity of a battery is usually given in mAh (milliampère-hours) or Ah (ampère-hours). To translate this to coulombs, note that 1Ah = 3600 coulomb (or use http://www.rapidtables.com/convert/charge/ah-to-coulomb.htm).

 

[Drakkith]

Say that 6V battery is connected to a lamp that takes 3V from each coulomb. Does that mean that the battery can supply 6V or dependent upon the need of components in the circuit ?

Hi Sam. Is there any way you could clarify what you're asking using standard terminology? It sounds like you're referring to a lamp which has a voltage drop of 3 volts. Voltage drop is the loss of energy as current flows through a circuit. A voltage drop of 3 volts means that for every coulomb of charge that passes through the lamp, 3 joules of energy are "lost" to the lamp, leaving a remaining 3 joules/coulomb for the rest of the circuit.

Does that mean that the battery can supply 6V or dependent upon the need of components in the circuit ?

It means that while the battery is supplying 6 volts to the circuit as a whole, only half of that is being used by the lamp. The other 3 volts are being used elsewhere in the circuit.