What does time=0 represent in kinematics

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Discussion Overview

The discussion revolves around the interpretation of time t=0 in kinematics, particularly in the context of throwing a ball upwards and projectile motion. Participants explore what t=0 signifies—whether it is the moment just before the ball is released or the moment immediately after release—and how this affects the velocity components of the ball.

Discussion Character

  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants propose that t=0 represents the moment when the ball is released, indicating that the velocity at this point is the initial velocity imparted to the ball, unaffected by gravity.
  • Others argue that t=0 can also be interpreted as the moment just before the ball is released, where the ball is still in contact with the hand and has not yet begun to experience gravitational acceleration.
  • A participant notes that in projectile motion, at t=0, the ball has zero vertical velocity and a non-zero horizontal velocity, questioning how this aligns with the effects of gravitational acceleration.
  • Another participant suggests that the distinction between "just before" and "just after" release becomes negligible in the limit of an infinitely small time interval.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the interpretation of t=0, with multiple competing views presented regarding its definition and implications for velocity components.

Contextual Notes

There are unresolved assumptions regarding the definitions of time intervals and the effects of gravity on the ball's motion at t=0. The discussion highlights the potential for different interpretations based on the chosen reference point for time.

Talha
So basically i am confused about time 0 in terms of kinamatics graphs
Lets say i throw a ball upwards so what does time t=0 represent, the time after which the ball is released or the time at which ball is about to be released?
Secondly in projectile motion if i throw a ball horizontally at a height then time zero has zero vertical velocity but a non zero horizontal velocity, why is that(considering the first option that it represents time after ball is released so it must have some vertical velocity even in points due to 9.8m/s^2 acceleration)?
 
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Typically t=0 is chosen to be the point where the ball is released. The velocity at t=0 is then the initial velocity you give the ball, unaffected by gravity.
The velocity for t>0 is affected by gravity.

Keep in mind that this choice is completely arbitrary. You can define that the ball is released at t=6436.83 s. Then gravity only affects the velocity for t>6436.83 s. It doesn’t change the motion of the ball, it just makes the calculation a bit more complicated.
 
Normally, the complete statement would be "t represents the time in seconds after the ball is released".

So t=0 is when the ball is about to be released and anything >0 is when the ball will have vertical velocity. Since this is the last instant where the ball is still in contact with your hand, this is the initial velocity given to the ball. Afterwards, it will experience acceleration/decelleration due to net force from external factors (air resistance and gravity)
 
Talha said:
So basically i am confused about time 0 in terms of kinamatics graphs
Lets say i throw a ball upwards so what does time t=0 represent, the time after which the ball is released or the time at which ball is about to be released?

The first case is just before the ball is released.
The second case is just after the ball is released.

In the limit (eg when "just before" or "just after" means an infinitely small amount of time) these are the same thing.

Secondly in projectile motion if i throw a ball horizontally at a height then time zero has zero vertical velocity but a non zero horizontal velocity, why is that(considering the first option that it represents time after ball is released so it must have some vertical velocity even in points due to 9.8m/s^2 acceleration)?

It's so soon after release that the vertical velocity might as well still be zero.
 

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