What Does Trace(p^4-p^3) Equal for a 2x2 Complex Matrix with Given Properties?

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For a 2x2 complex matrix P with trace(P) = 1 and det(P) = -6, the eigenvalues are calculated as a = (1 + i√23)/2 and b = (1 - i√23)/2. The expression for trace(P^4 - P^3) can be simplified using the properties of traces, specifically that trace(P^n) is the sum of the eigenvalues raised to the nth power. Therefore, trace(P^4 - P^3) equals trace(P^4) - trace(P^3). The final result hinges on evaluating these traces based on the derived eigenvalues.
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Homework Statement



Let P be 2x2 complex matrice such that trace(p)=1 det(p)=-6 then trace(p^4-p^3) equals what...?



Homework Equations



Is there any formula for trace(A^n)

The Attempt at a Solution



Let the two eigen values be a,b

a+b=1 a*b= -6 solving we get a=(1+i√23)/2 and b =(1-i√23)/2

Trace(p^4-p^3)=trace(p^4)-trace(p^3)
 
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ajayguhan said:

Homework Statement



Let P be 2x2 complex matrice such that trace(p)=1 det(p)=-6 then trace(p^4-p^3) equals what...?

Homework Equations



Is there any formula for trace(A^n)

The Attempt at a Solution



Let the two eigen values be a,b

a+b=1 a*b= -6 solving we get a=(1+i√23)/2 and b =(1-i√23)/2

Trace(p^4-p^3)=trace(p^4)-trace(p^3)

Trace identities: http://en.wikipedia.org/wiki/Trace_(linear_algebra)
 
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