Probability of Getting Head or 4: 7/12

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Homework Help Overview

The discussion revolves around calculating the probability of getting a head when flipping a coin and rolling a die, specifically focusing on the event of obtaining either a head or a 4 on the die.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the sample space and event definitions, questioning the inclusion of the event "H, 4" in the probability calculation. There is discussion about the meaning of "or" in the context of probability and whether it implies both events can occur.

Discussion Status

Participants are actively clarifying the definitions of events and the implications of using "or" in probability. Some guidance has been offered regarding the correct interpretation of events and the use of probability formulas, but there is no explicit consensus on the final approach.

Contextual Notes

There is a noted confusion regarding the interpretation of events and the necessity of including specific outcomes in the probability calculation. Participants reference previous discussions for context, indicating ongoing exploration of the topic.

alijan kk
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Homework Statement


If a coin flipped and one die is thrown, what is the probability of getting a head or a 4 ?

Homework Equations

The Attempt at a Solution


Sample Space={ H,1 H,2 H,3 H,4 H,5 H,6 T,1 T,2 T,3 T,4 T,5 T,6 }
Event={ H,1 H,2 H,3 H,5 H,6 T,4 }
probability is 6/12

if i don't do it with the formula P(A)+P(B)-P(AintersectionB)

i know the probability is 7/12

but what does probability of " a head or a 4" really mean ? should i add H,4 in the set of event but why it is necessary if yes
 
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alijan kk said:

Homework Statement


If a coin flipped and one die is thrown, what is the probability of getting a head or a 4 ?

Homework Equations

The Attempt at a Solution


Sample Space={ H,1 H,2 H,3 H,4 H,5 H,6 T,1 T,2 T,3 T,4 T,5 T,6 }
Event={ H,1 H,2 H,3 H,5 H,6 T,4 }
You left out the event H, 4.
alijan kk said:
probability is 6/12

if i don't do it with the formula P(A)+P(B)-P(AintersectionB)

i know the probability is 7/12

but what does probability of " a head or a 4" really mean ? should i add H,4 in the set of event but why it is necessary if yes

From the other thread you started (now deleted):
alijan kk said:
but what does probability of " a head or a 4" really mean ? should i add H,4 in the set of event but why it is necessary if yes
Yes you should add H, 4 to the events you're looking at. "A head or a 4" means that the coin turned up with a head OR the 4 on the die was on top OR both.
 
Mark44 said:
You left out the event H, 4.
H or 4 does that not mean either H or either 4 ? what is the difference in " H and 4 "
 
alijan kk said:
H or 4 does that not mean either H or either 4 ? what is the difference in " H and 4 "
No, "or" here does not mean "either H or 4." It includes the possibility of both occurring.
So P(H or 4) consists of the events {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 4)}.
P(H and 4) consists of only one event: {(H, 4}}.
 
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Mark44 said:
No, "or" here does not mean "either H or 4." It includes the possibility of both occurring.
So P(H or 4) consists of the events {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 4)}.
P(H and 4) consists of only one event: {(H, 4}}.
Thanks again <3
 
but what does probability of " a head or a 4" really mean ?
Don't get confuse .Be clear with event.
P (AUB) = P (A)+P (B)- P (A intersection B)
Use this formula if A intersects B.

P (AUB) = P (A)+P (B) => use this formula if A does not intersect B.
 

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