What does 'with the vertical' mean in circular motion problems?

[ehf]

Homework Statement

(please ignore something that is not english)

Homework Equations

ac=v^2/r
Fc is about 6.0E3 N and ac is about 5.0 m/s^2
(b) is the problem...

The Attempt at a Solution

what is 'with the vertical' here? the direction/opposite of ac or the direction of v?

 

[.Scott]

It means the angle with the vertical. So a strictly vertical force downward would be 0 degrees. A strictly horizontal (sliding) force would be 90 degrees.

 

[ehf]

sliding=horizontal=velocity direction and vertical=ac direction then?

 

[.Scott]

sliding=horizontal=velocity direction and vertical=ac direction then?

The force applied to the car by the pavement will consist of 2 components:
- 1) There will be a vertical component that supports the mass of the car against gravity.
- 2) There will be a horizontal centripetal force that holds the car along its circular path.

The angle of the total force against the car with vertical will be an arc tangent of the ratio of these forces.

 

[ehf]

The force applied to the car by the pavement will consist of 2 components:
- 1) There will be a vertical component that supports the mass of the car against gravity.
- 2) There will be a horizontal centripetal force that holds the car along its circular path.

The angle of the total force against the car with vertical will be an arc tangent of the ratio of these forces.

Oh thank you now I understand the meaning