What does x = x_0 + O(y) mean?

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Thread starter AxiomOfChoice
Start date Aug 5, 2009
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AxiomOfChoice

Thread starter
Aug 5, 2009

Can someone please explain what it means to say something like
[tex] x = x_0 + \mathcal{O}(y)[/tex]
?

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arildno

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Aug 5, 2009

Nothing.

You must include in your expression a "as x goes to.."

Without that, it is meaningless.

g_edgar

Aug 5, 2009

[itex]\cos x = 1 + O(x^2)[/itex] as [itex]x \to 0[/itex] means:
[tex]\frac{\cos x - 1}{x^2}[/tex]
is bounded in some neighborhood of [itex]0[/itex] .

What does x = x_0 + O(y) mean?

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What does x = x_0 + O(y) mean?

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