What Eigenvalues Lead to Square-Integrable Eigenfunctions?

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Felicity
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Homework Statement



solve the eigenvalue problem

(-∞)x dx' (ψ(x' ) x' )=λψ(x)

what values of the eigenvalue λ lead to square-integrable eigenfunctions?


The Attempt at a Solution



(-∞)xdx' (ψ(x' ) x' )=λψ(x)

differentiate both sides to get

ψ(x)x=λ d/dx ψ(x)


ψ(x)x/λ= d/dx ψ(x)

2xe x^2 =d/dx e x^2

so ψ(x) = e x^2 and λ = 2

but this is not square integrable so either this is incorrect or there are other solutions I am not seeing

Can anyone help me find what I am missing?

Thank you
 
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You want to solve the differential equation, ψ(x)x/λ= d/dx ψ(x) Separate the variables. You should get a solution with a lambda in it. Figure out what values of lambda make it square integrable.
 
Hello,
I think there are other solutions.
Take your equation,
[tex]x\psi\left(x\right) = \lambda\frac{d}{dx}\psi\left(x\right)[/tex]
and substitute [tex]\psi\left(x\right) = \exp\left(f\left(x\right)\right)[/tex] and see if you don't get an equation for [tex]f\left(x\right)[/tex] which has a solution that depends on [tex]\lambda[/tex].

Also, don't forget your solution has to be finite at the lower endpoint of the integral ([tex]-\infty[/tex]) in the original problem statement.
 
Dick said:
You want to solve the differential equation, ψ(x)x/λ= d/dx ψ(x) Separate the variables. You should get a solution with a lambda in it. Figure out what values of lambda make it square integrable.

ok i separated variables, integrated and got

ψ(x)=e1/(2λ) x2

however I don't see how this can be square integrable since for any value of λ I can think of the integral of the square will equal infinity. I feel like I am missing something obvious here but I don't know what it is
 
Felicity said:
ok i separated variables, integrated and got

ψ(x)=e1/(2λ) x2

however I don't see how this can be square integrable since for any value of λ I can think of the integral of the square will equal infinity. I feel like I am missing something obvious here but I don't know what it is

Will it equal infinity even if lambda is negative?
 
of course! I am so embarrassed, thank you