What Explains the Lack of Current in a PN Junction at Equilibrium?

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SUMMARY

The discussion focuses on the lack of current in a PN junction at equilibrium, specifically addressing the roles of drift and diffusion currents. In a PN junction, electrons from the N side and holes from the P side create an electric field that leads to a depletion region, resulting in zero net current. The drift currents, driven by the electric field, and diffusion currents, driven by thermal motion, cancel each other out, maintaining equilibrium. The terms "drift currents" and "diffusion currents" are essential for understanding this phenomenon.

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unified
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TL;DR
I am considering a PN junction at equilibrium, and have a couple of questions.
Consider a PN junction doped with say phosphorous on the N side, and Boron on the P side. Initially, there is an opportunity for the electrons just below the N conduction band to drop to the lower available energy states just above the P valence band. This leaves the N side positively charged and the P side negatively charged, forming a depletion region. This means that there will be an electric field pointing in the direction from N to P. Eventually, there will be an equilibrium that is reached, in which case there is no current in the depletion region.

I do not know which of the following explains why there is no current in the depletion region under equilibrium.
1. The electric field causes electrons from the negatively charged P side to flow back to the N type, and in equilibrium this cancels the flow of electrons from N to P. Also, the electric field causes holes to flow from N to P, and this cancels any holes flowing from P to N. The result of these processes is zero net current.
2. There is no current flowing either from N to P or P to N in equilibrium. In equilibrium, the depletion region is essentially an insulator, and while we have an electric field present in the region, the charge is not free to flow.
 
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(2) is clearly wrong. The holes and electrons are free to move. (1) is closer, but isn't very clearly stated. Exactly which currents cancel? Try drawing a sketch to show the various currents.
 
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phyzguy,

A sketch would include four currents, two from the field (electrons move against the field, holes with the field) and two due to random thermal motions (electrons from P to N, holes from N to P). In equilibrium these effects cancel.
 
unified said:
phyzguy,

A sketch would include four currents, two from the field (electrons move against the field, holes with the field) and two due to random thermal motions (electrons from P to N, holes from N to P). In equilibrium these effects cancel.
Exactly. This is much more clearly stated than your original (1). In semiconductor nomenclature, the currents driven by the electric field are typically called "drift currents" and the currents due to random thermal motions are typically called "diffusion currents". The drift currents obey Ohm's law (J = σE), and the diffusion currents are driven by concentration gradients and obey Fick's law (J=-D∇n).
 
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