What factors determine the maximum power of a 4-stroke engine per cylinder?

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SUMMARY

The maximum power of a 4-stroke engine per cylinder can be estimated using specific calculations involving octane rating, RPM, cubic centimeters (CC), bore and stroke dimensions, and volumetric efficiency. For example, the Boss 302 Mustang, rated at 444 hp at 7400 RPM, demonstrates this calculation with an airflow rate of 550 CFM derived from a volumetric efficiency of 0.85. The mass flow rate of air is calculated to be 2506 lb/hr, leading to a fuel burn rate of 186 lb/hr, which translates to a brake horsepower of 452 using a brake specific fuel consumption (BSFC) of 0.37 lb/hr-hp. The constant 3456 is a conversion factor used in these calculations to ensure unit compatibility.

PREREQUISITES
  • Understanding of volumetric efficiency (VE)
  • Familiarity with brake specific fuel consumption (BSFC)
  • Knowledge of cubic inches displacement (CID)
  • Basic principles of thermodynamics in engine performance
NEXT STEPS
  • Research the calculation of volumetric efficiency in various engine types
  • Explore the impact of octane ratings on engine performance
  • Learn about brake specific fuel consumption variations across different fuels
  • Investigate the relationship between bore, stroke, and engine power output
USEFUL FOR

Engineers, automotive enthusiasts, and performance tuners interested in understanding and optimizing the power output of 4-stroke engines.

oldboyonrgv
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Is there any equation for calculating the maximum power possible for a given 4 stroke engine? per cylinder.
I guess it would involve:
Octain rating of fuel used
RPM
CC
some factor of bore X Stroke
And an efficiency of 100%!
 
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Yes, you can figure from brake specific fuel consumption, displacement, and volumetric efficiency. I have a book I will try to find and get back to you...
 
OK, here is a simple approach for rough estimating. Actual engine power is based on many more variables that this method does not account for.

Lets try this for the new Boss 302 Mustang rated at 444 hp at 7400 rpm.

Compute the air flow rate at peak horsepower:

CFM = (VE)(CID)(RPM) / 3456 = (0.85)(302)(7400)/3456 = 550 cfm

A volumetric efficiency of 0.85 was assumed.

The mass flow rate of air:

mass_air = density X CFM = 0.076 lb / hr X 550 cfm = 2506 lb/hr

Now air and gasoline burn at a ratio of about 15:1, so the rate fuel is burned:

mass_fuel = mass_air / AF ratio = 2506 lb/hr / 15 = 186 lb/hr.

We convert the mass_fuel to power with "book value" of brake specific fuel consumption:

brake_hp = mass_fuel / bsfc = 186 lb/hr / 0.37 lb /hr-hp

brake_hp = 452

which is reasonable compared to published value of 444 hp.
 
Cool but I have some questions:
what is the 3456 number ? is it just a constant that should be used?
The book value is that a constant...
 
oldboyonrgv said:
Cool but I have some questions:
what is the 3456 number ? is it just a constant that should be used?
The book value is that a constant...
The 3456 number is a constant "conversion factor" to make all the units work.

And the book value can also be considered constant although bsfc for gasoline is a measured parameter and you will see some variation in the published values.
 
oldboyonrgv said:
Cool but I have some questions:
what is the 3456 number ? is it just a constant that should be used?
The book value is that a constant...

12 cubed (converting feet to inches), multiplied by 2 = 3456
 
OK thanks guys got it.
 

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