What Force is Needed to Move and Maintain an Ice-Fishing Hut?

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SUMMARY

The discussion focuses on calculating the forces required to move and maintain an ice-fishing hut weighing 52N on a frozen lake. The initial horizontal force needed to start sliding the hut is determined using the static friction equation, while the force required to maintain constant speed involves kinetic friction. The normal force (FN) is given as 52N, and the mass of the hut is calculated to be 5.3 kg. The coefficients of static (Us) and kinetic (UK) friction are essential variables that need to be defined for complete solutions.

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Homework Statement



An ice-fishing hut weighing 52N sits on dry, frozen lake.
(a). What is the magnitude of the initial horizontal force required to make the ice-fishing hut start sliding across the surface of the frozen pond?
(b). Once the ice-fishing hut has begun sliding, what force is required to maintain the hut sliding at a constant speed?

Given:
FN: 52N

Homework Equations



Us=Fs/FN

UK=FK/FN

The Attempt at a Solution



I figured out the mass is 5.3 kg by using the formula m=Fg/g and I'm not sure quite what to do next I feel as if some information is lacking? And I'm not quite sure if this question has acceleration and if it does is the acceleration for part (a) is 0?
 
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Sace Ver said:
Us=Fs/FN

UK=FK/FN

Just re-arrange these equations to put the friction force on one side. You are given the normal force, but it looks like you are not given the two coefficients of friction, so just keep them as variables in your answers.
 

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