What Force Must a Window Washer Exert to Ascend at Constant Speed?

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The window washer must exert a force equal to the gravitational force acting on her and the bucket to ascend at a constant speed. Given a combined mass of 63 kg, the gravitational force (Fgravity) is calculated as 617.4 N using the equation F = m(g), where g is 9.8 m/s². The tension in the rope (Ftension) must equal this gravitational force for the system to maintain constant speed, confirming that the downward pull must also be 617.4 N. A free body diagram is essential for visualizing the forces involved in this scenario.

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Homework Statement



A window washer pulls herself upward using the bucket-pulley apparatus:

4-40.gif


The mass of the person plus the bucket is 63 kg.

(a) How hard must she pull downward to raise herself slowly at constant speed?

Homework Equations



F = m(a)

The Attempt at a Solution



I figured that since she wants to raise herself at constant speed, that makes her acceleration equal to zero. Which means Fnet=0=Ftension-Fgravity, so Ftension=Fgravity. F gravity=9.8(63)=617.4 N, but it says I have the wrong answer.

Thanks in advance for the help.
 
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meganw said:

Homework Statement



A window washer pulls herself upward using the bucket-pulley apparatus:

4-40.gif


The mass of the person plus the bucket is 63 kg.

(a) How hard must she pull downward to raise herself slowly at constant speed?

Homework Equations



F = m(a)

The Attempt at a Solution



I figured that since she wants to raise herself at constant speed, that makes her acceleration equal to zero. Which means Fnet=0=Ftension-Fgravity, so Ftension=Fgravity. F gravity=9.8(63)=617.4 N, but it says I have the wrong answer.

Thanks in advance for the help.
you need to draw a good free body diagram. Isolate the woman , bucket and both cords by drawing a circle around them that cuts thru the cords, and identify all forces acting.
 

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