What Formula Do I Use to Find Instantaneous Velocity?

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SUMMARY

The discussion centers on calculating instantaneous velocity, defined as the speed of an object at a specific moment in time, akin to a car's speedometer reading. Instantaneous velocity can be determined graphically as the slope of the tangent line on a displacement vs. time graph or mathematically as the first derivative of the position function with respect to time in calculus. For example, if an object accelerates from 3 m/s at 5 m/s² for 7 seconds, the instantaneous velocity can be calculated as 38 m/s. Additionally, the discussion illustrates that for horizontal motion, such as a ball thrown off a cliff, the horizontal component remains constant while the vertical component increases due to gravity.

PREREQUISITES
  • Understanding of basic physics concepts, particularly velocity and acceleration.
  • Familiarity with calculus, specifically derivatives.
  • Knowledge of graphical analysis, particularly displacement vs. time graphs.
  • Basic understanding of the Pythagorean theorem for vector calculations.
NEXT STEPS
  • Study the concept of derivatives in calculus to better understand instantaneous velocity.
  • Learn how to analyze displacement vs. time graphs to find slopes and instantaneous rates of change.
  • Explore examples of motion in physics, particularly problems involving constant acceleration.
  • Investigate vector components of motion, including horizontal and vertical velocities in projectile motion.
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Students in physics courses, educators teaching kinematics, and anyone interested in understanding motion and velocity calculations.

Iceclover
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I was just confused on what formula i use to find instantaneous velocity if anyone can give me an example or explain how i figure it out that would be great. thanks!
 
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Formula? Well, not specifically a formula. However, you understand what instantaneous velocity is, right? It's what the speedometer of the car says (plus the direction the car is traveling.) If the car is traveling at a constant speed, then the instantaneous speed is the same speed throughout the time it's traveling.

If you look at it in a graphical sense; specifically a graph of displacement vs. time, the instantaneous velocity is the rate of change of the curve at any particular point. (Also stated as the slope of the curve, or more correctly, the slope of the tangent line to the curve at a point.) If you're in a calculus based physics course, the instantaneous velocity would be the first derivative of the position function, with respect to time.
 
i still don't really get it?
 
If you are using calculus in your physics class, then the instantaneous velocity is the derivative of the displacement function.

If you're not using calculus, then, I suppose, the answer is "it all depends."
For example, if an object starts at 3 m/s, and accelerates at 5 m/s^2 for 8 seconds, and you're wondering what the instantaneous velocity is after 7 seconds, then just treat the 7 second time as when a final velocity occurs. i.e. 3m/s + 5 m/s^2 * 7s = 38m/s

If you throw a ball horizontally at 10 m/s off a cliff, then the horizontal component of velocity will always be 10m/s (til it hits the ground, and as usual, ignoring air resistance.) The vertical component of velocity will be increasing at 9.81 m/s^2. So, after 3 seconds, it's vertical component of velocity will be 3 * 9.81 m/s = 29.43 m/s. You can find the instantaneous velocity at the 3 second point by applying the pythagorean theorem.

If you have a car traveling at a constant velocity of 4 m/s East, then at the 1 second point, 2 second point, and any other point in time while it's moving, the instantaneous velocity is 4m/s East.

Perhaps if you put your question into context, I could help you better.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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