What happen if i put r=0 into the formula F=(k)mm/r^2

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In summary, when plugging in r=0 into the formula F=(k)mm/r^2, the force becomes infinitely large in a mathematical sense. However, in reality, it is not possible to have two masses in exactly the same place, so the formula is not endlessly applicable. It is also important to consider quantum mechanics when dealing with very small scales, as the simple approach of a well-defined distance may fail.
  • #1
garylau
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What happen if i put r=0 into the formula F=(k)mm/r^2
So 1/0=infinity ?

then F= infinite large in mathematical sense?
is that statement correct ?

thank
 
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  • #2
That's what happens with the formula. In reality you can't have two masses in exactly one place, so the formula isn't endlessly applicable...

Mathematically you have a singularity.
 
  • #3
BvU said:
That's what happens with the formula. In reality you can't have two masses in exactly one place, so the formula isn't endlessly applicable...

Mathematically you have a singularity.
But In reality i can have two mass put in r=0.000001m
So the force still become very large?
 
  • #4
garylau said:
What happen if i put r=0 into the formula F=(k)mm/r^2then F= infinite large in mathematical sense?
is that statement correct to say F is infinitely large?

You cannot put in r = 0. That does not make sense. It does make sense to consider:

##\lim_{r \to 0}F = +\infty##. This means, intuitively, when ##r## approaches ##0##, ##F## becomes larger and larger (F grows without bound).
 
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  • #5
garylau said:
But In reality i can have two mass put in r=0.000001m
So the force still become very large?
Well, the masses become smaller too for such small particles. One micron diameter with a reasonable density gives a very small mass !

On even smaller scales still other things happen. Protons, for example have a mass of only 1.67 10-31 kg and a diameter of 0.88 10-15 m. At such small scales other kinds of forces are much stronger.
 
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  • #6
BvU said:
Well, the masses become smaller too for such small particles. One micron diameter with a reasonable density gives a very small mass !

On even smaller scales still other things happen. Protons, for example have a mass of only 1.67 10-31 kg and a diameter of 0.88 10-15 m. At such small scales other kinds of forces are much stronger.
is it possible that the mass is very large but the r is very small?
 
  • #7
garylau said:
is it possible that the mass is very large but the r is very small?
Yes. Moreover, in quantum physics mass is, in a certain sense, proportional to ##1/r##.
 
  • #8
garylau said:
is it possible that the mass is very large but the r is very small?
Yes, then you get a very large force. But it is always finite. And if you want to put the masses too close, you have to consider quantum mechanics where the simple approach with a well-defined distance fails.
 

1. What does the formula F=(k)mm/r^2 represent?

The formula F=(k)mm/r^2 represents the force of attraction between two masses, m and m, separated by a distance of r.

2. Why is r^2 in the denominator of the formula?

The r^2 in the denominator represents the inverse square law, which states that the force of attraction between two masses is inversely proportional to the square of the distance between them. This means that as the distance increases, the force decreases exponentially.

3. What units should be used for the variables in this formula?

The units for the variables in this formula are typically the standard units of mass (kg), distance (m), and force (N).

4. What happens if r=0?

If r=0, the formula would be undefined as it would result in division by zero. In terms of the force of attraction between two masses, it would mean that the masses are in the same exact location and therefore there would be no distance between them, resulting in an infinite force of attraction.

5. How does changing the value of k affect the force of attraction?

Changing the value of k, which represents the gravitational constant, would affect the force of attraction between two masses by either increasing or decreasing the overall force. A larger value of k would result in a stronger force of attraction, while a smaller value of k would result in a weaker force of attraction.

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