What Happens to the Speed and Proximity of Two Charged Metal Spheres in Motion?

  • Thread starter Thread starter Digdug12
  • Start date Start date
  • Tags Tags
    Metal Spheres
Click For Summary
SUMMARY

The discussion focuses on the dynamics of two charged metal spheres, specifically a stationary sphere with a charge of q_1 = -2.60 µC and a moving sphere with a charge of q_2 = -7.70 µC. The moving sphere, with a mass of 1.40 g, is projected towards the stationary sphere at a speed of 22.0 m/s when they are 0.800 m apart. The problem involves calculating the speed of the moving sphere when the distance between the two spheres reduces to 0.450 m, utilizing principles of conservation of energy and electric potential energy.

PREREQUISITES
  • Understanding of electrostatics and point charges
  • Familiarity with conservation of energy principles
  • Knowledge of electric potential and potential energy equations
  • Basic skills in algebra and physics problem-solving
NEXT STEPS
  • Study the conservation of energy in electrostatic systems
  • Learn about electric potential energy between point charges
  • Explore the concept of electric fields and their effects on charged particles
  • Investigate the equations governing motion under electrostatic forces
USEFUL FOR

Students studying physics, particularly those focusing on electrostatics and energy conservation, as well as educators looking for practical examples of these concepts in action.

Digdug12
Messages
15
Reaction score
0

Homework Statement


A small metal sphere, carrying a net charge of q_1 = -2.60 \mu C, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q_2 = -7.70 \mu C and mass 1.40 g, is projected toward q_{1}. When the two spheres are 0.800 \rm m apart, q_{2} is moving toward q_{1} with speed 22.0 \rm m/s . Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.
What is the speed of q_{2} when the spheres are 0.450 m apart
?How close does q_{2} get to q_{1}?


Homework Equations


Ka+Ua=Kb+Ub
U=qv
V=k(q1/r)




The Attempt at a Solution


I figured this was a simple conservation of energy problem, so i began it at such.
.5m2Vi^2 + q2Va = .5m2Vf^2 + q2Vb

after simplifying it all down i got:
sqrt((m2vi^2 + q2(Va-Vb))/m2) = Vf

I calculated Va to be -29233V and Vb to be -51952V. I am not sure what i did wrong here.
to calculate V i used q1, the charge of motionless sphere, since V is independent of the observer charge. For the r i used the distance from the moving sphere to sphere, and i used both values. when multiplying (Va-Vb) by q i used the q value of the moving sphere. Please help!
 
Physics news on Phys.org
What's the electrical potential energy between two point charges?
 

Similar threads

Replies
6
Views
2K
Replies
8
Views
12K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
23
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K