What Happens to Time Dilation at a Black Hole's Event Horizon?

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SUMMARY

The discussion focuses on the implications of gravitational time dilation as described by the equation T = T0 / √(1 - (2GM / rc²). It establishes that at the event horizon of a black hole, where r equals 2GM/c², the square root becomes zero, indicating that a stationary observer cannot exist at this point. The conversation clarifies that while M (mass) can be large, it cannot yield a negative result in the context of time dilation, and that r (radius) must remain greater than 2GM/c² to avoid undefined or imaginary outcomes.

PREREQUISITES
  • Understanding of gravitational time dilation
  • Familiarity with the Schwarzschild radius
  • Basic knowledge of general relativity
  • Mathematical proficiency with square root functions and limits
NEXT STEPS
  • Research the Schwarzschild solution in general relativity
  • Explore the concept of event horizons in black hole physics
  • Study the implications of infinite mass in gravitational equations
  • Learn about the behavior of light and observers near black holes
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Physicists, astrophysicists, and students studying general relativity and black hole dynamics will benefit from this discussion.

JohnGano
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I'm looking at this equation for gravitational time dilation:

<br /> T = \frac{T_0}{\sqrt{1 - (2GM / rc^2)}} <br />

I understand the relation of time dilation and velocity, and how v must be less than c, but I don't understand what exactly is implied here. At a certain point, M could be great enough such that the square root becomes negative or 0, or r could become small enough that the same thing happens. So what exactly does that mean? Is it possible that M or r could be a size such that you get an imaginary or undefined answer?
 
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JohnGano said:
I'm looking at this equation for gravitational time dilation:

<br /> T = \frac{T_0}{\sqrt{1 - (2GM / rc^2)}} <br />

I understand the relation of time dilation and velocity, and how v must be less than c, but I don't understand what exactly is implied here. At a certain point, M could be great enough such that the square root becomes negative or 0, or r could become small enough that the same thing happens. So what exactly does that mean? Is it possible that M or r could be a size such that you get an imaginary or undefined answer?
Sure. If M were infinite or r were zero, your answer could be 0. But how useful a solution is that in describing anything in the universe?

But no, it could never be negative.
 
JohnGano said:
I'm looking at this equation for gravitational time dilation:

<br /> T = \frac{T_0}{\sqrt{1 - (2GM / rc^2)}} <br />

I understand the relation of time dilation and velocity, and how v must be less than c, but I don't understand what exactly is implied here. At a certain point, M could be great enough such that the square root becomes negative or 0, or r could become small enough that the same thing happens. So what exactly does that mean? Is it possible that M or r could be a size such that you get an imaginary or undefined answer?

The square root becomes zero just at the event horizon of a black hole, where r=2GM/c^2. This is an indication of the fact that one cannot have a stationary observer exactly at the event horizon (one could have a stationary light beam, but a light beam isn't an observer).

One also cannot have a stationary observer inside the event horizon, i.e r < 2GM/c^2.

r here is the schwarzschild r cooridnate, btw.
 

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