labview1958 Messages 37 Reaction score 0 Thread starter Mar 29, 2010 #1 If the frequency of a water wave is doubled in a ripple tank, is the wavelength halved? The depth of water is kept constant.
If the frequency of a water wave is doubled in a ripple tank, is the wavelength halved? The depth of water is kept constant.
Fightfish Messages 953 Reaction score 118 Mar 29, 2010 #2 Yes. In shallow water, the speed of the water waves is dependent only on the depth (and the gravitational acceleration g). The general expression for the speed of a water wave is given by: [tex]v = \sqrt{\frac{g\lambda}{2\pi}\,tanh(2\pi\frac{d}{\lambda}})[/tex] which simplifies in the shallow depth limit into [tex]v = \sqrt{gd}[/tex]
Yes. In shallow water, the speed of the water waves is dependent only on the depth (and the gravitational acceleration g). The general expression for the speed of a water wave is given by: [tex]v = \sqrt{\frac{g\lambda}{2\pi}\,tanh(2\pi\frac{d}{\lambda}})[/tex] which simplifies in the shallow depth limit into [tex]v = \sqrt{gd}[/tex]
labview1958 Messages 37 Reaction score 0 Mar 30, 2010 #3 so, v=freq x wavelength Thus double the frequency the wavelength is halved in shallow water.