What Happens When Multiple Slits Are Used for Diffraction?

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SUMMARY

The discussion focuses on the principles of Fraunhofer diffraction, specifically deriving the expression for a single slit and exploring the implications of using multiple slits. The derived formula for the distance between a minimum and the central point is y = mλD/a, where D is the distance to the screen and a is the slit width. The conversation also raises questions about the diffraction patterns produced by double and multiple slits, as well as the effects of obstacles in the path of light.

PREREQUISITES
  • Understanding of Fraunhofer diffraction principles
  • Familiarity with wave optics terminology
  • Knowledge of slit width and distance parameters in diffraction
  • Basic grasp of light behavior around obstacles
NEXT STEPS
  • Research the mathematical derivation of double slit diffraction patterns
  • Explore the concept of interference in multiple slit arrangements
  • Study the effects of obstacles on light propagation and diffraction
  • Learn about the applications of diffraction patterns in optical instruments
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Students and educators in physics, optical engineers, and anyone interested in the behavior of light in diffraction scenarios.

carlosbgois
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Hi there. It's not actually a problem, I was just trying to figure it out, so idk if this is the right section for this post, but anyways: I've managed to derive the expression for the Fraunhofer diffraction in a single slit, such that the distance between a minimum and the central point is given (in an approximation) by [itex]y=\frac{mλD}{a}, m=1, 2, 3, ...[/itex], in which D is the distance from the slit to the screen, and a is the slit gap.

What would happen in the same arrangement, but with a double slit? And with multiple slits? And what if, instead of a slit, I had an obstacle, such that the light would (classicaly) go through the sides, but not over the object?

Many thanks
 
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