Dennmac
- 2
- 3
So we know [Sz, Sx] = ihbar Sy (S with hats on) so what happens if you get [Sx, Sz]? Is it the same result? Just trying to work out if I've gone wrong somewhere
The discussion focuses on the commutation relation between spin operators, specifically examining the relationship between [Sz, Sx] and [Sx, Sz]. It is established that [Sz, Sx] = ihbar Sy, and by the properties of commutators, [Sx, Sz] = -ihbar Sy. The participants confirm that the results are consistent with the fundamental commutation relations in quantum mechanics.
PREREQUISITESStudents of quantum mechanics, physicists specializing in quantum theory, and researchers exploring quantum computing and spin dynamics.
In general ##[A, B] = - [B, A]##. The proof is as easy as they come.Dennmac said:So we know [Sz, Sx] = ihbar Sy (S with hats on) so what happens if you get [Sx, Sz]? Is it the same result? Just trying to work out if I've gone wrong somewhere