What Happens When You Throw a Ball on Mars?

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Homework Help Overview

The discussion revolves around a physics problem involving projectile motion on Mars. The original poster presents a scenario where a ball is thrown vertically with an initial speed and height, and gravity on Mars is specified. The questions focus on determining maximum height, time in the atmosphere, speed upon impact, height after a specific time, and speed at a certain height.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various equations of motion, including SUVAT equations, to analyze the problem. There are attempts to calculate time to maximum height and maximum height itself, with some participants questioning the appropriateness of the equations used. Others express uncertainty about their understanding of the concepts involved.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and clarifying concepts. Some guidance has been offered regarding the use of specific equations, and there is a recognition of the need to approach the problem step by step. Multiple interpretations of the problem and its components are being explored.

Contextual Notes

Participants note varying levels of familiarity with physics concepts, indicating that some are new to the subject and may require more foundational explanations. There is also mention of the need to clarify the meanings of different types of velocity in the context of the problem.

wonchristy
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A ball is thrown with an initial speed of v0=39.2m/s vertically to Mars. Its initial height is h=15m from the surface of mars. the acceleration of gravity on Mars is g=3.7m/s^2

(1) what is the maximum height hmax of the ball

(2) How long is the ball in the 'atmosphere'

(3) What is the speed vG of the ball when it hits the surface of Mars

(4) What is the height of the ball after exactly 5s?

(5) When the ball's height is 7m, what is the speed?

This is my homework. Could anyone explain this in the EASIEST way possible? :(
 
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Can you show what you have tried so far?
 
@Rocket50

Sure, this is my very first baby thread and I almost have no background in Physics so please don't make fun of me haha

(1) So, at maximum height, v=0m/s
First I'm tried to find t
x=1/2at+vt
v=at+v0
=gt+32.9=0
gt=-32.9
t=-32.9/g
t=-3.4

it takes -
and then i don't know what to do from here

honestly that's all i hace so far.. :( i can try to work on it more and come back
we can try to do this one question by one question.. :)

thanks
 
(1)

yf=y0+voyt+1/2at^2?
 
@CWatters Hey thanks for the reply! No i am in PHYS101 so no not yet. :(

Or is this an elementary physics equation lol
 
I googled questions asking for maximum height and I think this person used the SUVAT equation?
 

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Make sure when you use these equations, you use the velocity in context with respect to its meaning. Avg, initial, final, inst.
 
wonchristy said:
(1) So, at maximum height, v=0m/s
First I'm tried to find t
x=1/2at+vt
v=at+v0
=gt+32.9=0
gt=-32.9
t=-32.9/g
t=-3.4
If upwards velocity is a positive number, then acceleration downwards is a negative number.
t = 3.4 s
correct formula where to plug that time: x =1/2at²+vt

Then I guess one might calculate various things regarding a ball falling down from height x.
 
  • #10
A ball is thrown with an initial speed of v0=39.2m/s vertically to Mars. Its initial height is h=15m from the surface of mars. the acceleration of gravity on Mars is g=3.7m/s^2
(1) what is the maximum height hmax of the ball

For this one I would use

V^2 = U^2 +2as

which doesn't involve time at all.
 

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