A ball thrown straight upward reaches a maximum height of 18 meters. To determine the height at which the ball's speed is halved, one must apply the principles of kinematics and energy conservation. Given the initial velocity (vi) is zero at the peak and gravitational acceleration (g) is 9.81 m/s², the height can be calculated using the formula for potential energy and kinetic energy relationships. The specific height where the speed is half of the initial speed is found to be 13.5 meters above the launch point.
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mandaa123 said:Homework Statement
A ball is thrown straight upward and rises to a maximum height of 18 m above its launch point. At what height above its launch point has the speed of the ball decreased to one-half of its initial value?
Homework Equations
i don't know.
The Attempt at a Solution
vi=0, d=18m, g=9.81, this is all i know.