What Height Will the Block Reach After Leaving the Spring?

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SUMMARY

The discussion focuses on calculating the maximum height a green block will reach after compressing a spring. The block falls at a speed of 20 m/s from a height of 7 meters, and the spring constant is 4155 N/m. The spring compresses by 10.6 cm when the block impacts it. To determine the maximum height after leaving the spring, the conservation of energy principle is applied, emphasizing that the initial kinetic energy at the height of 7 meters is converted into potential energy at the maximum height.

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Homework Statement


The green block is falling at a speed of 20 m/s and is 7 meters above the spring. The spring constant is 4155 N/m, to the nearest tenth of a cm how far is the spring compressed?

The answer to that part is 10.6cm

The next part is what I'm having difficulty with...

In the previous problem to the nearest hundredth of a meter to what height will the block rise after it hits and leaves the spring?


Homework Equations



V= (fx/m)^.5 which is the exity velocity I think. How will I find the maximum height?
 
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Iamaskier721 said:

Homework Statement


The green block is falling at a speed of 20 m/s and is 7 meters above the spring. The spring constant is 4155 N/m, to the nearest tenth of a cm how far is the spring compressed?

The answer to that part is 10.6cm

The next part is what I'm having difficulty with...

In the previous problem to the nearest hundredth of a meter to what height will the block rise after it hits and leaves the spring?

Homework Equations



V= (fx/m)^.5 which is the exity velocity I think. How will I find the maximum height?
The question is actually a little simpler than you're making it out to be. If we assume that energy is conserved then the previous part of the question is irrelevant. All you need to know is that when the block is 7 meters above the spring it is traveling at 20m/s. What do you know about the velocity, and consequently the kinetic energy of the block at it's maximum height?
 

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