What is a non-rectifiable bounded closed set in \mathbb{R}?

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Homework Help Overview

The discussion revolves around identifying a bounded closed set in \(\mathbb{R}\) that is not rectifiable, as posed in a question from "Analysis on Manifolds" by Munkres. The original poster expresses difficulty in approaching this problem and seeks hints to guide their understanding.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to construct a closed set whose boundary does not have measure zero, considering the need for an uncountable union of intervals. Some participants suggest the "fat Cantor set" as a potential example, prompting further reflection on the characteristics of such sets.

Discussion Status

Participants have provided hints that seem to guide the original poster toward a viable direction, specifically mentioning the fat Cantor set. There is an acknowledgment of the learning process, with the original poster expressing gratitude for the hints received.

Contextual Notes

The original poster notes previous consideration of the standard Cantor set, indicating a potential misunderstanding of the properties required for the problem at hand.

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Homework Statement


I am trying to work my way through Analysis on manifolds by Munkres. Question 14.5 has me stumped. Any hints on how to tackle it would be appreciated. The question is:

Find a bounded closed set in [tex]\mathbb{R}[/tex] that is not rectifiable

Homework Equations



A subset S of [tex]\mathbb{R}[/tex] is rectifiable iff S is bounded and the boundary of S has measure zero.

The boundary of an interval in [tex]\mathbb{R}[/tex] has measure zero.

The Attempt at a Solution



I think I need a closed set who's boundary does not have measure zero. I presume it has to be an uncountable union of intervals of some description, but I have no idea how to approach the construction of such a thing.
 
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Hint: fat Cantor set. Look it up.
 
Dick said:
Hint: fat Cantor set. Look it up.


Thank you. I should have thought of that, but only considered the standard Cantor set. Thanks again.
 
GreyZephyr said:
Thank you. I should have thought of that, but only considered the standard Cantor set. Thanks again.

Wow! That was fast. I see that "a word to the wise is sufficient" is sometimes true.
 
Dick said:
Wow! That was fast. I see that "a word to the wise is sufficient" is sometimes true.

I have come across fat cantor sets before and my problem was that I could not think of a closed set whose boundary had positive measure. As soon as you gave the hint the rest followed and I felt like a fool. Oh well such is the learning process. Thanks again for the help, I had been stuck on that for a couple of days.
 

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