What is a Vector: Sadri Hassani's Maths Physics Reading

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The forum discussion centers on the abstract definition of vectors as presented in "Reading in Mathematical Physics" by Sadri Hassani. Key properties of vectors include their ability to be added and multiplied by scalars, with specific rules governing these operations. The conversation also clarifies that scalars and vectors can be considered as tensors of rank 0 and 1, respectively. Additionally, it emphasizes the importance of transformation rules in understanding the generalization of vectors and tensors.

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Reading in Mathematical Physics by Sadri Hassani. It defines a vector abstractly. I will repeat that definition here rather more informally.

There are these things called vectors, a, b, x etc., that have these properties:

You can add them
a + b = b + a
a + (b + c) = (b + a) + c
a + 0 = a, 0 is the zero vector
a + (- a) = 0

You can multiply them by complex numbers (scalars) like c, d
c(d a) = (cd)a
1 a = a

Multiplication involving vectors and scalars is distributive
c(a + b) = c a+ c b
(c + d) a = c a+ d a

And that is it.

Given that definition, a scalar is a vector, a matrix is a vector, a tensor is a vector. Yes?

Mind you, I have also read that scalars and vectors are a kinds of tensors, of rank 0 and 1 respectively. True?

Am I confused? Should I be?
 
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tobor8man said:
Reading in Mathematical Physics by Sadri Hassani. It defines a vector abstractly. I will repeat that definition here rather more informally.

There are these things called vectors, a, b, x etc., that have these properties:

You can add them
a + b = b + a
a + (b + c) = (b + a) + c
a + 0 = a, 0 is the zero vector
a + (- a) = 0

You can multiply them by complex numbers (scalars) like c, d
c(d a) = (cd)a
1 a = a

Multiplication involving vectors and scalars is distributive
c(a + b) = c a+ c b
(c + d) a = c a+ d a

And that is it.

Given that definition, a scalar is a vector, a matrix is a vector, a tensor is a vector. Yes?

Mind you, I have also read that scalars and vectors are a kinds of tensors, of rank 0 and 1 respectively. True?

Am I confused? Should I be?

you shouldn't be confused... you'll learn that first) ther's not only euclidean geometry----> different metrics----> then a vector is a generalization of a tensor, you'l learn the meaning of covarianca and controvariance... and you'll understand that everything id defined by its tranformation rule...

say an euclidean vector V is something that |V|^2 is an invariant under SO(3) and that under rotation transform as: [tex]V'^{\mu}=R_{\mu\nu}V^{\nu}[/tex] where R belongs to SO(3).
keep going...
regards
marco
 
A vector is an element of a vector space. Thus, elements of the real line are vectors if you endow the real line with the algebraic structure of a vector space. The set of all continuous functions over R is also a vector space, where the vectors are functions. Tensors with the usual addition are also elements of a vector space when regarded in that manner. This is a space where the vectors are tensors, and so forth.
 

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