What is an approximate amplitude of a phonon?

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SUMMARY

The discussion centers on the amplitude of phonons, which are lattice vibrations influenced by temperature. At room temperature, the energy per degree of freedom is given by ##\frac{1}{2} k_B T##, where ##k_B## is the Boltzmann constant. The relationship between the energy of an elastic wave and the amplitude is established through the equation (1/2)ρω²Amplitude² = nħω, linking the energy of the wave to the phonon occupancy number. The total energy of vibrating atoms is derived from both kinetic and potential energy, resulting in a total of six degrees of freedom in a simple Einstein model.

PREREQUISITES
  • Understanding of phonons and lattice vibrations
  • Familiarity with thermodynamic concepts, particularly heat capacity
  • Knowledge of elastic wave equations and energy relations
  • Basic grasp of quantum mechanics, specifically phonon occupancy numbers
NEXT STEPS
  • Research the relationship between phonon occupancy numbers and temperature
  • Learn about the Debye model and its implications for phonon behavior
  • Explore the derivation of energy equations for elastic waves in solids
  • Study the Einstein model of solids and its application to phonon energy
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Physicists, materials scientists, and engineers interested in solid-state physics, particularly those studying lattice dynamics and thermal properties of materials.

Karthiksrao
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I am aware that phonons are lattice vibrations - and that the amplitude of vibration would depend on the temperature. But say, at room temperature what would the order of magnitude of these lattice vibrations be ?

In particular, in continuum limit these phonons can be treated as elastic waves. So if I have take an incident planar longitudinal elastic wave at a surface, what would I need to take the amplitude of this wave to be ?

I do think that if I equate the energy stored in this wave integrated over all incident angles and frequencies to the heat capacity of the solid - I should be able to find the amplitude of this wave. Is this correct ?

Thanks!
 
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I think I figured it out. Each mode will be populated by a number of phonons equal to the phonon occupancy number, each with energy h v, and the energy of each mode can be related to the amplitude of the lattice vibration.
 
I'm glad that you answered your own question. However, this might help:
Room temperature is well above Debye's temperature for most solids. The energy per degree of freedom is then ##\frac 1 2 k_B T ##
 
Thanks for the note. I always get confused - what is the relation between a degree of freedom and a mode/state? Are they the same?

For example, in my case, I have (1/2 rho omega^2 Amplitude^2) = n * hbar omega

The left hand side is the energy contained in the elastic wave; and the right hand side is the energy contained by the total number of phonons occupying the state ('n' is occupation number for the frequency omega).

So in terms of degrees of freedom you mentioned, is it just that (1/2 rho omega^2 Amplitude^2) = 1/2 k_B T ?

Thanks
 
Total energy of vibrating atoms is kinetic and potential. Kinetic is a function of momentum that has 3 components - 3 degrees of freedom. Potential is a function of displacement, again in 3 dimensions - 3 degrees of freedom. Total is 6 degrees of freedom. So, in a simple, Einstein model ## \frac 1 2 \kappa x^2 = \frac 1 2 k_B T## where ##\kappa ## is the 'spring' constant.
 

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