What Is Discretization in Temperature Change Analysis?

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SUMMARY

Discretization in temperature change analysis involves approximating the derivative of a temperature function over time using finite differences. The discussion highlights the use of forward and backward difference methods to calculate the rate of change, represented as dT/dt. Specifically, the formulas (T2-T1)/(t2-t1) and (T1-T2)/(t1-t2) are utilized for first-order approximations. The accuracy of these approximations improves with smaller time intervals, and higher-order methods can be employed by incorporating more grid points.

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  • Understanding of basic calculus, specifically derivatives.
  • Familiarity with finite difference methods.
  • Knowledge of temperature change modeling and graphing.
  • Experience with numerical analysis concepts.
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  • Learn about higher-order discretization techniques.
  • Explore Newton's law of cooling and its mathematical implications.
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If I have a logged temperature change over time which makes up a plottet graph. I denote this change

[tex] {{dT} \over {dt}}[/tex]

People have told me this can be solved using discretization, but I have no idea what that is. Apparently it is something like this:

[tex] {{T_1 - T_2 } \over {\Delta t}}[/tex]

but I don't really know what it means. Also, isn't a differential equation supposed to end up as a function of some variable? If so, how can an approximation like this wind up as one? Could someone explain it to me? Thx :smile:
 
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TSN79 said:
If I have a logged temperature change over time which makes up a plottet graph. I denote this change

[tex] {{dT} \over {dt}}[/tex]

People have told me this can be solved using discretization, but I have no idea what that is. Apparently it is something like this:

[tex] {{T_1 - T_2 } \over {\Delta t}}[/tex]

but I don't really know what it means. Also, isn't a differential equation supposed to end up as a function of some variable? If so, how can an approximation like this wind up as one? Could someone explain it to me? Thx :smile:

Say you have logged time T = [T1,T2,T3...TN] over time values t = [t1,t2,t3,...tN]
now, if you do a plot of T vs t, you would get a curve. If all goes well, your plot may represent a function, say like Newton's law of cooling ..some exponential form may be available. Now, a continuous function like exp is continuously differentiable. Hence, assume you got a solution

T =f(t),
at any time t, you can get dT/dt leading to

dT/dt = f'(t) evaluated at some time t.

Now, this is straightforward.

Also, thiink abt a curve made up of discrete points.

So to get a change or derivative (the slope), we can also do

dT/dt at t1 = (T2-T1)(t2-t1) like forward differenced

or dT/dt at t1 = (T1-T2)/(t1-t2) backward differenced.

However, since these are first order approximations of the original functions, f(t) , your solution of evaluating dT/dt is first order accurate.

Higher order can be achieved by taking more grid points. Look at finite difference approximations.

the smaller the difference between t1 and t2, the better approximation of your time derivative.
 

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