Enthalpy (H) is defined as the sum of internal energy (U) and flow work (p⋅V), expressed as H = U + p⋅V. In isentropic processes, where no heat is transferred, the enthalpy difference corresponds to the work performed by or on the fluid. For flow systems, the change in enthalpy per unit mass is calculated using the specific heat capacity (Cp) and the temperature change of the gas parcels. This approach is essential for determining exit temperatures in systems operating at steady state.
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This is incorrect. In a reversible Carnot cycle, which is an isentropic process, the change in enthalpy is zero, and the work is equal to the net heat transferred. Even for an isentropic reversible single-step change for a closed system, it is the internal energy which is equal to minus the work done on the surroundings, not the enthalpy.stockzahn said:Enthalpy H is the sum of the internal energy U and the flow work p⋅V.
H = U + p⋅V
In an isentropic process no heat is transferred, the enthalpy difference of the fluid corrisponds to the work performed by/on the fluid.
Yes, sorry I forgot to add that.Chestermiller said:Apoorv312: Are you asking about an open system operating at steady state when you ask "how do we use it to calculate the total heat transfer in isentropic processes?"
Thank you sir, that really helped.Chestermiller said:For a flow system like the one described, you first follow each little parcel of gas going through the system, and treat it as a closed system that is subjected to an adiabatic reversible expansion to the final pressure exiting your device. On this basis, you determine the temperature change for each of the parcels. This will determine the exit temperature from your flow system. The change in enthalpy per unit mass flowing through your system is then equal to Cp times the temperature change.
Chet