What Is Her Apparent Weight in a Decelerating Elevator?

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SUMMARY

The discussion focuses on calculating the apparent weight of a 58.0 kg girl in a decelerating elevator. When the elevator descends at a speed of 10 m/s with a deceleration of 2.5 m/s², her apparent weight is determined by the equation: apparent weight = weight due to gravity - (mass × deceleration). The initial weight calculated was 568 N, and by applying the deceleration, the correct apparent weight can be derived.

PREREQUISITES
  • Understanding of Newton's Second Law (Force = Mass × Acceleration)
  • Basic knowledge of gravitational force calculations
  • Familiarity with concepts of acceleration and deceleration
  • Ability to apply physics equations to real-world scenarios
NEXT STEPS
  • Study the effects of acceleration on apparent weight in different scenarios
  • Learn about the physics of elevators and forces acting on objects within them
  • Explore advanced topics in dynamics, including free body diagrams
  • Investigate real-world applications of Newton's laws in engineering
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of dynamics and forces in motion, particularly in relation to elevators and apparent weight calculations.

shimizua
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Homework Statement


Referring to the problem above, if the elevator's descending speed is measured at 10 m/s at a given point, but its speed is decreasing by 2.5 m/s2, what is her apparent weight?.
And the problem above it was this
A 58.0 kg girl weighs herself by standing on a scale in an elevator. What is her apparent weight when the elevator is descending at a constant speed of 10 m/s?


Homework Equations


So i was able to find the answer to the first question which was 568N and found it by doing her mass times the gravity. but i have no i idea of how to do it when the speed it decreasing.


The Attempt at a Solution


i tried doing her mass times her acceleration which was 10m/s and that was wrong and so i then tried doing her mass time her deceleration of 2.5m/s/s and that was wrong as well. if you could just help with an equation that should be good enough. thanks
 
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Her apparent weight will be the weight due to gravity plus the force exerted on her by the lift.
 
Last edited:
ok so i would use my initial number of 568N and add that to what? her mass times the deceleration?
cool so i put that in and it does work, thanks man
 
Yes, force = mass times acceleration. If the elevator is accelerating upward, then you would feel g+ mass * acceleration. If the elevator is accelerating downward, then you would feel g- mass*acceleration.
 

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