What is her speed relative to the ice surface?

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SUMMARY

The discussion revolves around calculating the speed of a girl walking on a plank that is sliding on a frictionless ice surface. The girl has a mass of 44 kg and walks at a speed of 1.37 m/s relative to the plank, which has a mass of 170 kg. The correct approach involves using the principle of conservation of momentum rather than directly calculating force. The girl's speed relative to the ice surface is determined to be 1.016 m/s after accounting for the plank's movement.

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Ry122
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A 44 kg girl is standing on a plank that has a mass of 170 kg. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless supporting surface. The girl begins to walk along the plank at a constant speed of 1.37 m/s relative to the plank.
What is her speed relative to the ice surface?

My attempt:
The horizontal force the girl exerts on the plank is f=1.37(44)=60.28N
so the speed of the plank relative to the ice should be 60.28=170a a=.354ms
and her speed relative to the ice should be 1.37-.354=1.016
but this is incorrect, what am i doing wrong?
 
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Ry122 said:
The horizontal force the girl exerts on the plank is f=1.37(44)=60.28N

Here's at least one error in your thinking: How can a force be a speed times a mass?
 


where do i begin then?
 


would momentum be involved?
 

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