What is mathematically wrong with this integration?

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EngWiPy
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Hello all,

I have the following integration:

[tex]\int_{-\infty}^{\infty}e^{-j2\pi f_ct[a_p-a_q]}g(t[1+a_p]-kT_s-\tau_p)g(t[1+a_q]-mT_s-\tau_q)\,dt[/tex]

where g(t) is 1 in the interval [0,Ts]. This means that the integration has value when both function g(t[1+a_p]-kT_s-\tau_p) and g(t[1+a_q]-mT_s-\tau_q) are 1. Both are 1 when:

[tex]0\leq t[1+a_p]-kT_s-\tau_p\leq T_s[/tex]

and

[tex]0\leq t[1+a_q]-mT_s-\tau_q\leq T_s[/tex]

Which implies that both are 1 when:

[tex]t=\frac{(\tau_p-\tau_q)+(k-m)T_s}{a_p-a_q}[/tex]

But the integration over a point is zero, which can be the answer of the physical problem I have in hand. Where did I go wrong in the process?

Thanks.
 
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S_David said:
Which implies that both are 1 when:

[tex]t=\frac{(\tau_p-\tau_q)+(k-m)T_s}{a_p-a_q}[/tex]


This is where you went wrong. You can't use the two inequalities to evaluate t directly. You need to calculate the range of t where the two functions are both nonzero.

For example le[itex]\tau_p=\tau_q=a_p=a_q=0[/itex],
[itex]k=-1[/itex],
and
[itex]m=-2[/itex]

Now
[itex]g(t[1+ap]−kTs−τp) =1[/itex] for [itex]t\in(0,1)[/itex]
and
[itex]g(t[1+aq]−mTs−τq) =1[/itex] for [itex]t\in(0,.5)[/itex]

As you can see there is still a range in [itex]t[/itex] where both g are nonzero.
 
the_wolfman said:
This is where you went wrong. You can't use the two inequalities to evaluate t directly. You need to calculate the range of t where the two functions are both nonzero.

For example le[itex]\tau_p=\tau_q=a_p=a_q=0[/itex],
[itex]k=-1[/itex],
and
[itex]m=-2[/itex]

Now
[itex]g(t[1+ap]−kTs−τp) =1[/itex] for [itex]t\in(0,1)[/itex]
and
[itex]g(t[1+aq]−mTs−τq) =1[/itex] for [itex]t\in(0,.5)[/itex]

As you can see there is still a range in [itex]t[/itex] where both g are nonzero.

When I subtract the ranges of both functions I got something like:

[tex]0\leq x\leq 0[/tex]

which implies that x=0. Right?
 
But if I add the ranges I'll get a range of t! Which one is more correct? and why?