What is the Acceleration of a Dropped Shell?

  • Thread starter Thread starter Brit412
  • Start date Start date
  • Tags Tags
    Acceleration
Click For Summary

Homework Help Overview

The problem involves a glaucous-winged gull dropping a shell from a height of 11.5 meters while ascending at a speed of 5.10 m/s. The focus is on determining the magnitude of the shell's acceleration immediately after release.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial conditions of the shell's motion and the implications of free fall. There is an attempt to apply kinematic equations, but confusion arises regarding the correct interpretation of acceleration just after release.

Discussion Status

Some participants have provided insights suggesting that the problem may not require complex calculations and that the shell's acceleration is influenced by gravitational forces. Others are exploring how to approach finding the maximum height of the shell, indicating a shift in focus from the initial question.

Contextual Notes

There is mention of a potential misunderstanding regarding the height from which the shell is dropped, as well as the need for clarity on the relationship between the shell's initial conditions and its subsequent motion.

Brit412
Messages
24
Reaction score
0

Homework Statement



A glaucous-winged gull, ascending straight upward at 5.10 m/s drops a shell when it is 11.5m above the ground. What is the magnitude of the shell's acceleration just after it is released?

Homework Equations


The only equation that I can think of would be v^2= v(i) + 2a (x-x(0)) because I have no time value

The Attempt at a Solution


Using this equation I got an answer of 1.13 m/s^2, but on my hw, it claims it's incorrect. So help please!
 
Physics news on Phys.org
This sounds like one of those questions where the book is trying to trick you into thinking the problem needs more work than is necessary.

Before the bird let's go of the shell it has zero acceleration since it is moving up at a constant speed with the bird. When the bird let's go of the shell it enters free fall. That should give you your answer.
 
Thanks, you were right. But question, how am I supposed to find the maximum height? Apparently it's not 11.5m, so how would I start approaching the problem?
 
Use the constant acceleration formulas. In fact there is one formula that relates all the variables you have to part of the answer you are looking for; it doesn't involve time.
 
Last edited:

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
13
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K