What is the acceleration of an electron in an electron gun?

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SUMMARY

The acceleration of an electron in an electron gun is calculated using the formula vf = vi + at. Given an initial speed (vi) of 10^3 m/s and a final speed (vf) of 4×10^5 m/s over a time interval of 1 microsecond (1×10^-6 s), the correct acceleration (a) is determined to be 3.99×10^11 m/s². The book's answer of 3.99×10^9 m/s² is incorrect, confirming that the user's calculation is accurate.

PREREQUISITES
  • Understanding of kinematic equations, specifically vf = vi + at
  • Basic knowledge of units of measurement, particularly meters per second (m/s) and seconds (s)
  • Familiarity with scientific notation and its application in physics
  • Concept of electron dynamics in electric fields
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  • Review kinematic equations in physics for motion analysis
  • Study the principles of electron acceleration in electric fields
  • Explore the concept of scientific notation in physics calculations
  • Investigate common errors in physics textbooks and how to identify them
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Students studying physics, particularly those focusing on electromagnetism and kinematics, as well as educators seeking to clarify common misconceptions in textbook problems.

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Homework Statement


Q; In an electron gun of television set, an electron with initial speed of 10^3m/s enters a region where it is electrically accelerated. It emerges out of this region after 1micro sec with speed of 4×10^5 m/s.

(a) Find the acceleration.

Homework Equations


vf= vi+at

The Attempt at a Solution


vf = vi+at
400000= 1000+a*0.000001
400000-1000= a*0.000001
399000=a*0.000001
399000/0.000001= a
3.99×10^11= a
a= 3.99×10^11


The ans in book is 3.99×10^9

Which ans is right ?
Any help would be appreciated :-) :-D ,
Thank you
 
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##4.10^5=10^3+a.10^{-6}##
Your ans is right
 
Hamal_Arietis said:
##4.10^5=10^3+a.10^{-6}##
Your ans is right
My ans is right !
That means book has a mistake,
Thanks
 

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