What is the acceleration of m2 in a frictional pulley system?

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SUMMARY

The acceleration of mass m2 in a frictional pulley system can be calculated using the forces acting on both masses. Given mass m1 at 34.3 kg and mass m2 at 5.30 kg, with a force of 201.7 N applied at an angle of 32.1 degrees and a coefficient of kinetic friction of 0.185, the upward acceleration of m2 can be determined. The equations used include F_horizontal = F_given * cos(theta), F_friction = mgμ_k, and the net force equation F_horizontal - F_friction - T = m1 * a. The tension T in the string is also expressed as T = m2 * a + m2 * 9.81.

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qi0n
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Homework Statement



Mass m1=34.3 kg is on a horizontal surface, connected to mass m2= 5.30 kg by a light string as shown. The pulley has negligible mass and no friction. A force of 201.7 N acts on m1 at an angle of 32.1o.
The coefficient of kinetic friction between m1 and the surface is 0.185. Determine the upward acceleration of m2.

Homework Equations



F_given * cos(theta) = F_Horizontal
F_friction = mgμ_k
F_horizontal - F_friction - T = m_1 * a
T = m_2 * a + m_2 * 9.81

The Attempt at a Solution


F_horizontal - F_friction - m_2 * 9.81 = m_1 * a + m_2 * a
 
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qi0n said:

Homework Statement



Mass m1=34.3 kg is on a horizontal surface, connected to mass m2= 5.30 kg by a light string as shown.

Nothing is shown!

ehild
 

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