What is the acceleration of objects falling on the moon in a vacuum?

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SUMMARY

Objects falling on the Moon in a vacuum experience the same constant acceleration due to gravity, which is approximately 1.625 m/s². This acceleration remains constant regardless of the object's mass, similar to the behavior of falling objects on Earth, where gravity exerts an acceleration of about 10 m/s². The discussion clarifies that while velocity increases as objects fall, the acceleration does not change, confirming that the correct answer is option c: the same constant acceleration.

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Ok the question I have is pretty simple

we claimed thatif the air resistance could be neglected all objects on hte moon wuld fall at
a. the same constant speed
b. an increasing acceleration
c. the same constant acceleration
d. a decreasing acceleration

Ok so i know its not the same constant speed, because the acceleration is what changes. And I know the acceleration isn't decreasing, or it would be getting slower and stop mid air...which obviously doesn't happen. So I'm torn between b and c, an increasing acceleration and the same constant acceleration. If we use the rule that gravity pulls us 10 m/s-squared then it would have the same acceleration the whole time and the velocity would increase, so the answer has to be c right?

...ok now that I'm confused hopefully someone agrees with me or can explain why that's wrong.
 
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As long as we are only talking about objects near the moon's surface, then they all fall with the same acceleration--for the same reason that falling objects near the Earth's surface all have the same acceleration (ignoring air resistance). The acceleration due to gravity near the Earth's surface is about 10 m/s^2. Would you expect the acceleration due to gravity on the moon to be the same? smaller? greater?
 
I agree with you. That is assuming that the object is at small distances wrt the moons radius.

EDIT: Beaten to it by a better explanation.
 

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